Recent content by sweetdion

so how would we relate the Ic with the square to find part b? This must be Faraday's law...

Solenoid Passing through square coil--Finding electric field Homework Statement A very long solenoid with n turns of wire per unit length and radius b carries a current I(t) which decays with time as I(t)=I0e-t/T. The direction of current in the solenoid is as shown below. The solenoid passes...

Homework Statement Given the following circuit: What is the actual voltage provided to the circuit by the non-ideal battery if the internal resistance r = 0.50 ohms and the internal emf is 9.0 volts? A. 9.8 V B. 8.5 V C. 9.0 V D. 8.4 V E. 8.8 V Homework...

Okay, So I see what your saying. The correct answer would be E. I and IV, unless I've got something wrong out of your explanations...

well the resistors on the outer edges of the diamond are in series. You can reduce those to one resistor each. Then you have 3 resistors in parallel which you can reduce...i think

Thanks Melawrghk. :)

I was assuming just for the time being because I hadn't solve the equations for I yet. I actually found the current to be 1.43 Amps. So substitute that in for I instead.

I don't even know what you mean by the delta to Y transformation :redface:

Homework Statement Which of the following circuits could be reduced to a single resistance and a battery by determining the equivalent resistance using combinations of resistors in series and parallel? A. II and IV only B. I and II only C. II and III only D. I and III...

Is it correct to assume that at the top of the branch the potential is 0?

Moving on to part C now. When the switch is closed for a very long time, the capacitor starts discharging through the resistors. After a long time, the voltage across the capacitor becomes equal to the voltage across the 100 Ω resistor. V= IR=(0.05A)(100Ω)=5V

Oh. Now I see what I was doing wrong. Simple Math error. I = 0.05A

A lot, 6000. Which, is wrong. I'm asking for your help because I don't understand what I'm doing wrong, ehild.

Yeah, that's what I meant.

I solved the top equation and that's what I got. Did I label my currents right?