Recent content by swimgirl5892

  1. S

    Arc length: Can't Solve the Integral

    I got it! The answer is \frac{53}{6}. Thank you!
  2. S

    Arc length: Can't Solve the Integral

    Ok, so then when I find an LCD I get: \int\sqrt{\frac{8(x+1)^4}{16(x+1)^4}+\frac{16(x+1)^8}{16(x+1)^4}+\frac{1}{16(x+1)^4}} which simplifies to \int\frac{4(x+1)^4 +1}{4(x+1)^2} Is this as simple as possible? I'm afraid I still can't integrate this...
  3. S

    Arc length: Can't Solve the Integral

    Find the exact length of the curve analytically by antidifferentiation: y = (x3/3) + x2 + x + (1/(4x +4)) on the interval 0 < x < 2So I set it up using the length of a curve formula: L = \int\sqrt{1+(x^2+2x+1+(\frac{-1}{4(x+1)^2}} And simplified it to L =...
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