Recent content by Tan Bee Yong

Ok .. will give it another try.. thank you so much for helping

LHS has a pair of complex conjugate roots, hence my Yc = e2x(Dcos(x) + Ecos(x)) i thought this is a special case, that's why I use Cxe2x Did I make a mistake at the complementary function?

Yp = Ax + B + pxe2x Yp' : A + pe^2x + 2pxe2x Yp'' 2pxe2x + 2pxe2x + 4pxe2x=4pe2x+ 4pxe2x substitute the above into the DE. i get: 4pe2x + 4pxe2x -4A-4pe2x - 8pxe2x + 5Ax + 5B + 5pxe2x =-4A + 5Ax + 5B + pxe2x by comparing with the right-hand side of DE; 5Ax = 25x A= 5, -4A +...

particular solution = Ax + B + pxe^2x differential once : A + pe^2x + 2pxe^2x differential again 2pxe^2x + 2pxe^2x + 4pxe^2x=4pe^2x + 4pxe^2x substitute the above into the DE. i get: 4pe^2x + 4pxe^2x -4A-4pe^2x - 8pxe^2x + 5Ax + 5B + 5pxe^2x =-4A + 5Ax + 5B + pxe^2x by comparing...

Homework Statement This question concerns the second-order differential equation dy^2/dx^2 -4(dy/dx) + 5y = 25x - 3e^2x. Find the solution of the differential equation that satisfies the initial conditions y=0 and dy/dx= 0 when x=0. Homework Equations The Attempt at a Solution