Recent content by Taylan

Thank you! alright so: n1.T1./P1 = n2.T2./P2 n2= (n1.T1.P2)/(P1.T2) since T is constant: n2=(n1.P2)/P1 I know P1 (101300Pa) n1 can be found out from ideal gas law equation since P1, V1, T1 and R is known. about P2.. I know that the air will keep getting out until the pressure outside and...

oh ı see. okay thanks! so ı guess since V and R are constant I am going to further rearrange it and say V/R = nT/P ? and then (nT/P)before= (nT/P)after ?

No, the pressure inside is 101300Pa and outside it is 99000Pa so some air will move outside due to the pressure difference. I don't think I am supposed to assume the temperature is constant in this specific question though

inside = 101300Pa and outside=99000Pa. The gas would move from higher to lower pressure and the movement would stop when the pressures are equal.

I thought I should use the ideal gas law to find out moles of air that would be transferred out through the window but the temperature and volume outside is not known. Can you help me further? thanks

Thanks a lot for the help!

A0.v0 = A.v .. and then setting up simultaneous equations?

yes

v^2 = u^2 + 2as

The thing is h gives the distance between A0 and A. However A0 is not where the water starts flowing. So at A0, it already has some velocity. ( that is what it looks to me from the attachment)

a) so Q=V/t = Av Q is constant ( same At A0 and A). That means I have to find the velocity of the water either at A0 or at A. But how can I find it? I thought there must be a reason that h is given but the only way I can use it is to assume the velocity is 0m/s at A0 but actually it is not...

thanks a lot!

Hm so i have to use the 500kg somehow. Can you give me more tip please? Not sure how to include the 500 kg

I guess when density of air = density of helium

So it means density of air decreases too