Recent content by tdog13

ΔI/I= √ (Δ.5/.5)^2 + (Δm/m)^2 + (ΔB/B)^2? And B would then be (2ΔB/B)^2... so ΔI/I= √ (Δm/m)2 + (2ΔB/B)2?

Yeah I see the difference between the 2 approaches. I wish I fully understand what you are conveying but I am only a first year health major forced to take physics and have never done so before or statistics for the matter so the language is kinda foreign ro me haha However, umm perhaps you can...

Link from first post indicating is rules is not working but I'm reading something else and since .5 is a constant... it is factored out. (m) would be (Δm/m) (r) would be 2(Δr/r) Since it is multiplication, putting it all together it would be... √ (Δm/m) + (2(Δr/r)) ...?

I thought I replied to this, I but I eventually got it... I am currently trying to do another one that deals with the formula for moment of intertia. I = .5mr^2. Would ΔI = √(.5(Δm/m))^2 + (2(Δr/r))^2 ?

Thank you and would be or is that total wrong lol Δg/g= ((dA/A)^2))+((dB/B)^2))

So in the first part.. would A= w^2 and B = L ...?

Homework Statement Converting the simple pendulum expression for g in terms of the angular frequency ω instead of the period T, where ω=2π/T, yields g=ω2L. Derive an expression for the error (Δg) in g by first setting g=A⋅B. A= B= Therefore in terms of A, ΔA, B, and ΔB: Δg/g= Converting back...