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    Newton's 3rd law, tension, friction

    Thank you! That helped. The accelerations where the boxes start to slide are: m1: 88.2 = 15 * a => a = 5.88 m2: 205.8 = (15+20) * a => a = 5.88 So they both slide at the same time. And in part e, since the acceleration is less than 5.88, they don't slide off.
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    Newton's 3rd law, tension, friction

    Homework Statement Homework Equations F=m*a Fs <= N*us Fk = N * uk The Attempt at a Solution b) T-fs = 120 T-.2 * 9.8 * (15 + 20 + 25) = 120 => T = 237.6 Newtons c) (Fs)2 on 1 = (Fs)1 on 2 = 15 * 9.8* .6 = 88.2 Newtons d) (15 + 20) * 9.8 * .6 = 205.8 Newtons e) This is...
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