Recent content by techgeek17

Significant Digits = 3 And the formula should be D(copper)*(1-c)+D(gold)*c=D(crown), right? If so, I got 3.52*10^-2 kg or .345 N How am I doing?

I believe I need to use 2 significant digits. So that would make my density 1.8x10^4, right? Also, I did some calculations and managed to get what looks like a possibly correct answer. Here's what I did: Formula: D(copper)*(c-1)+D(gold)*c=D(crown), where c is the ratio of gold to crown...

Whoops! I didn't catch that before I posted. The volume I calculated is supposed to be 2.0x10^-6 m^3 (got confused with the unit), not 10^6. and I wrote the apparent mass title based off the equation I used: m(in air) - m(apparent/in water) = d(water)*v , solving for v also density unit should...

OK, I attempted to find the volume and density. I got: mass(in air) as 36.5g appearant mass(in water) as 34.5g volume = 2.1x10^6 L(?) density = 1.83 x 10^4 kg/l I am assuming now that I need to find a percentage or something of the sort for the gold in the crown.

Homework Statement A jeweler has made a crown of an alloy of gold and copper. The crown weighs 0.358 N when measured in air and 0.338 N when submerged completely in water. The density of water is 1.00x10^3 kg/m^3, the density of copper is 8.92X10^3 kg/m^3, and the density of gold is 1.93x10^4...