Recent content by techiejan
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Graduate Solution of exponential equation
Thanks grzz. This was very helpful.- techiejan
- Post #5
- Forum: General Math
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Graduate Solution of exponential equation
Thanks grzz, I solved it now. Can you please tell me the logic behind expanding the exponential to first three terms?- techiejan
- Post #3
- Forum: General Math
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Graduate Solution of exponential equation
How does the given equation: βe^(x/β)-x = β+(A/B) solves to x = √(2A/βB) when β is large?- techiejan
- Thread
- Exponential
- Replies: 4
- Forum: General Math
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Graduate Minimizing x in "(A+Bx)/(1-e^(-βx))-(B/β)
Thank you very much! -
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Graduate Minimizing x in "(A+Bx)/(1-e^(-βx))-(B/β)
Thanks Math man, But how do I incorporate the constraint ? -
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Graduate Minimizing x in "(A+Bx)/(1-e^(-βx))-(B/β)
I really need this problem solved. Some help please. -
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Graduate Minimizing x in "(A+Bx)/(1-e^(-βx))-(B/β)
Thanks HallsofIvy. So let me get this correctly...for the above optimization, we just take derivative of the objective function? How do we incorporate the constraint in that case? In my case derivation of the objective function yields e^(βx)-βx=1-(βA)/B. And then considering 1/β is large, I... -
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Graduate Minimizing x in "(A+Bx)/(1-e^(-βx))-(B/β)
How to minimize the following: {(A+Bx)/(1-e^(-βx))}-(B/β) Subject to : x/(1-e^(-βx)))- (1/β)≤ T I need the find the value of x. All A,B,T and β are constants. The numerator is linear. I don't know if the equation remains linear when the denominator is added. When plotted, the equation is a...