Recent content by tehstone

Thank you! That was the correct solution.

I ran out of answer attempts so now I can't find out what the correct answer is. I tried both 3221 J and 3.2e3 J and neither were correct. Oh well, thank you very much for your help.

That would be Joules. and so to go from Newtons to Joules you have to include the distance over which the Newtons were exerted. I did that for the friction calculation. But the work done vs gravity shouldn't need it because gravity is conservative right? Edit: So to be clear, for the friction...

Homework Statement A father pushes horizontally on his daughter's sled to move it up a snowy incline, as illustrated in the figure, with h = 4.4 m and θ = 10°. The total mass of the sled and the girl is 35 kg and the coefficient of kinetic friction between the sled runners and the snow is...

It appears to me that you are using the diameter in your calculation rather than the radius. 2mg = m*v^2/r v = sqrt(2gr) v = sqrt(2*(9.8m/s^2)*20m) v = sqrt(392) = 19.798 which rounds up to 20 m/s If you do the same math with r = 40 you get 28 m/s. However, the question states that the...