Recent content by tehstone

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    Work done on incline with friction

    Thank you! That was the correct solution.
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    Work done on incline with friction

    I ran out of answer attempts so now I can't find out what the correct answer is. I tried both 3221 J and 3.2e3 J and neither were correct. Oh well, thank you very much for your help.
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    Work done on incline with friction

    That would be Joules. and so to go from Newtons to Joules you have to include the distance over which the Newtons were exerted. I did that for the friction calculation. But the work done vs gravity shouldn't need it because gravity is conservative right? Edit: So to be clear, for the friction...
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    Work done on incline with friction

    Homework Statement A father pushes horizontally on his daughter's sled to move it up a snowy incline, as illustrated in the figure, with h = 4.4 m and θ = 10°. The total mass of the sled and the girl is 35 kg and the coefficient of kinetic friction between the sled runners and the snow is...
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    Calculating Rotational Speed on a Giant Wheel

    It appears to me that you are using the diameter in your calculation rather than the radius. 2mg = m*v^2/r v = sqrt(2gr) v = sqrt(2*(9.8m/s^2)*20m) v = sqrt(392) = 19.798 which rounds up to 20 m/s If you do the same math with r = 40 you get 28 m/s. However, the question states that the...
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