Recent content by tessie0407

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    Looking for capacitive reactance but missing "C"

    The only other thing I can think to do is rearrange ΔVc= I*Xc Xc= ΔVc/I Xc= 10V/10x10^-2 A which gives me 100Ω
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    Looking for capacitive reactance but missing "C"

    [b]1. Current and voltage graphs are shown for a capacitor circuit with ƒ=1000Hz. What is the capacitive reactance Xc? [b]2. I know the equation is Xc= 1/2∏ƒC to solve for capacitive reactance but where do I find C? All of our in class examples had C and ƒ given. The...
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    Incredibly lost on Calorimetry Problem

    Oops, nevermind. I just realized that I am working on the patient specific heat not the alcohol.
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    Incredibly lost on Calorimetry Problem

    2430 J/kg degrees C is the specific heat for Ethyl Alcohol listed in my textbook. Is that what I am supposed to have in the equation?
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    Incredibly lost on Calorimetry Problem

    I've been working on this problem for hours and have come up with the following thus far. Can someone let me know if I am on the right track? Q(heat energy)=m(mass)*c(specific heat)*change of time Q=(75 kg)*(2430 J/kg degrees C)*(2.5 degrees C)= 455,625 Joules That portion is for the...
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    Incredibly lost on Calorimetry Problem

    Thank you. I was sure it was but he has never given a problem of this difficulty so I was sure that I was reading more into it. I appreciate the confirmation. I'm going to get to work on it and hope I can figure it out. Thanks again for the quick reply.
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    Incredibly lost on Calorimetry Problem

    Homework Statement An alcohol rub can rapidly reduce an elevated body temperature in a patient. The heat energy lost by the person is due to the evaporation of alcohol. Find the number of grams of alcohol that must be evaporated from the surface of a 75 kg person to reduce the body...
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