THanks a lot!
And sorry for the confusion, I meant dz/ds and dz/dt indeed. On a side note, what's the difference between writing dz/dt and t'? just curious
I think I got it
I ended up with (-1,-1) , (-1,1) , (1,-1) , (1,1)
and the three first are saddle points while the last one is a local minimum. Anyone correct me if the person attempts the problem. Thanks
Hi Tiny-Tim,
thanks for the quick reply!
I do understand I have to solve for 1+t = 0 as well as s+2t+1 =0
and 1+s = 0 and t+2s+1=0.
The difficulty I am having is with s+2t+1 =0 and t+2s+1=0. The two others are clearly s=t=-1
Therefore (-1,-1) is a solution. Now, how do I solve for...
Hey,
I have trouble finding the critical points for this function:
z = f(s,t) = (1+s)(1+t)(s+t)
I get that
s' = (1+t) (t+2s+1) = 0
t' = (1+s) (s+2t+1) = 0
So t= -1 and s= -1 is a C.P.
How do i solve for the others?
Any help is greatly appreciated thanks!