Recent content by th4m4ster

THanks a lot! And sorry for the confusion, I meant dz/ds and dz/dt indeed. On a side note, what's the difference between writing dz/dt and t'? just curious

I think I got it I ended up with (-1,-1) , (-1,1) , (1,-1) , (1,1) and the three first are saddle points while the last one is a local minimum. Anyone correct me if the person attempts the problem. Thanks

Hi Tiny-Tim, thanks for the quick reply! I do understand I have to solve for 1+t = 0 as well as s+2t+1 =0 and 1+s = 0 and t+2s+1=0. The difficulty I am having is with s+2t+1 =0 and t+2s+1=0. The two others are clearly s=t=-1 Therefore (-1,-1) is a solution. Now, how do I solve for...

Hey, I have trouble finding the critical points for this function: z = f(s,t) = (1+s)(1+t)(s+t) I get that s' = (1+t) (t+2s+1) = 0 t' = (1+s) (s+2t+1) = 0 So t= -1 and s= -1 is a C.P. How do i solve for the others? Any help is greatly appreciated thanks!