Some background info: I am an international student that is currently studying at a supposedly prestigious university (Top 20 in QS and Times Higher Education ranking). As part of my major requirement, I am taking an EM module. The problem is, my forte is not really physics (I am an IBO...
Homework Statement
Homework Equations
Gauss's Law
The Attempt at a Solution
I simply used logic and observed the symmetry of the cube. If the charge is placed on the middle of the cube, the flux would simply be Q/∈0. The face of the cube itself can be split into 4 squares, with the charge at...
Homework Statement
Homework Equations
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The Attempt at a Solution
I tried to break it down to:
But apparently it is incorrect, can someone tell me the correct configuration? And explain too! Thanks :)
(Please do not give ambiguous "hints").
Homework Statement
2. Homework Equations
Ohm's law and Kirchoff's voltage law
The Attempt at a Solution
My solution is a bit long so I will just briefly explain it. First, we find the total equivalent resistance. Since the circuit extends to infinity, it is equal to replacing the second...
My answer is only IV true, but in the answer key it is IV and V. How does the velocity drift stay the same in both cables?
vd1/vd2 = J1/nq1⋅ nq2/J2
vd1/vd2 = q2/q1
vd1/vd2 = 4q1/q1 (based on the relation that I1 = 1/4 I2)
vd1 = 4vd2
That is why I am asking whether other formula for velocity...
Homework Statement
Homework Equations
J = nqvd
J = I/A
Q = It
The Attempt at a Solution
Basically we check whether the variable that we are looking at is proportional or inversely proportional. However, at what part do we stop? Where is it okay to substitute say Q = It and where is it not...
I am a first year undergrad student majoring Biomedical Engineering. Though I may be in an engineering course, my forte is not exactly physics, but biology. In fact, one of the reasons I got accepted to my university is due to the medal from the International Biology Olympiad (IBO). I will be...
So if the question is asking for the "charge of the larger shell" it would be 91.6 + 3.3 μC, but since this question is only asking for the outer surface, the charge is taken to be 91.6 μC?
Ah I think I get it. Since the electric field inside a conductor must be 0, there must exist a charge on the inner surface of the larger shell that is equal and opposite to 3.3 μC. Thus, the remaining charge is 91.6 - 3.3 = 88.3 μC. Is this what you are hinting at?