Recent content by The_eToThe2iPi
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Undergrad Limitations of the Lebesgue Integral
But doesn't this also not have a Riemann integral over that same domain since ##\int^{1}_{\delta}\frac{1}{x}dx=[ln(x)]^{1}_{\delta}=ln(\frac{1}{\delta})## but ##ln(\frac{1}{\delta}) \to \infty## as ##\delta \to 0##?- The_eToThe2iPi
- Post #15
- Forum: Topology and Analysis
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Undergrad Limitations of the Lebesgue Integral
What domain are you integrating ##f(x)=\frac{1}{x}## over? Does an improper Riemann integral exist for ##f(x)=\frac{1}{x}## over that domain? The reason I used ##sin(x)/x## was because it is an alternating function and so needs to be broken down into it's positive and negative parts in order to...- The_eToThe2iPi
- Post #13
- Forum: Topology and Analysis
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Undergrad Limitations of the Lebesgue Integral
To be honest, I feel like these are the sort of questions that require me to read a book (and I'll probably have even more afterwards). Thank you all so much for answering my questions and pointing me in the right direction.- The_eToThe2iPi
- Post #11
- Forum: Topology and Analysis
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Undergrad Limitations of the Lebesgue Integral
Wow, just imagine if students had to buy all their own textbooks! £152! Fortunately I think the university has a copy of that one so I won't have to sell my kidney :) The page on gauge integration mentions that this integral can be extended more general domains and I was wondering whether...- The_eToThe2iPi
- Post #10
- Forum: Topology and Analysis
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Undergrad Limitations of the Lebesgue Integral
Ahh, that's interesting. I didn't think about that. But I still feel that there is a difference between the two instances. In your case we are evaluating two separate Riemann integrals, finding they are infinite, and then asking what their difference is like asking what is ##(a+\infty)...- The_eToThe2iPi
- Post #7
- Forum: Topology and Analysis
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Undergrad Limitations of the Lebesgue Integral
So I'm studying a course on measure theory and we've learned that the Lebesgue integral of a real function is (loosely) defined as the total area over the x-axis minus the total area under the x-axis. This seems to me to be limited because these areas can both be infinite but their difference...- The_eToThe2iPi
- Thread
- Integral Lebesgue integration
- Replies: 15
- Forum: Topology and Analysis