Recent content by TheRainMan713

I rewrote it three different ways and I'm still having a hard time seeing the complete pattern. I'm using the fourth derivative: f4(x)=(1/3)(-2/3)(-5/3)(-8/3)x-11/3 and: f4(x)=(1/3)(1/3-1)(1/3-2)(1/3-3)x-11/3 and:f4(x)=(1/3)(1/3-3/3)(1/3-6/3)(1/3-9/3)x-11/3 So far I have fn(x)=(-1)n+1(?/3n)x1/3-n

Homework Statement I'm trying to find a formula for the nth derivative for the function f(x)=x1/3 The Attempt at a Solution I know that it has alternating signs so it start with (-1)n+1 and I know the exponent for it is x(1/3-n) but I'm having a hard time figuring out the coefficient of x...