Wouldn't using the equation create a problem as you can not do everything you do to an equation to an inequality?
For eg: dividing both sides by - 1
* Also I apologize for my clumsiness for not finding the key for "|"
Well, I kind of did it in a long way;
If |x+3|> 0 then |x+3|= x+3, and substituted the term (x+3) to where |x+3| is found
this gives
if x> -3, x > -1
and did the same for the other condition
Homework Statement
Solve Ix+3I>2
*I is used for absolute value notation
The Attempt at a Solution
Considering both
a) Ix+3I > 0 then Ix+3I= x+3
b) Ix+3I < 0 then Ix+3I= -(x+3)
when solved this would yield to;
a) x>-3 and x>-1
b) x<-5 and x<-3
from my general reasoning i...