- #1

theself

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## Homework Statement

Solve Ix+3I>2

*I is used for absolute value notation

## The Attempt at a Solution

Considering both

a) Ix+3I > 0 then Ix+3I= x+3

b) Ix+3I < 0 then Ix+3I= -(x+3)

when solved this would yield to;

a) x>-3 and x>-1

b) x<-5 and x<-3

from my general reasoning i think the answer should be x>-1 and x<-5. Why are the solutions x>-3 and x<-3 omitted? Is it because the other two include a broader range?

thanks for your help.