I guess I'll reword my most basic question.
Let's say you have a shaft fixed at one end, free at the other. If you apply a torque at the midpoint, will there be a shear stress anywhere between where the torque is applied and the free end of the beam?
In this problem, if there isn't a shear...
Hello all,
I am working on a design project (school work, nothing too important) and I'm trying to wrap my head around how to analyze potential failure in a shaft with an applied tensile load at one end and a torque near the midpoint. (The beam is fixed at the other end.) The tensile force...
Homework Statement
A sample of an ideal gas goes through the process shown below. From A to B, the process is adiabatic; from B to C, it is isobaric with 98 kJ of energy entering the system by heat. From C to D, the process is isothermal; from D to A, it is isobaric with 158 kJ of energy...
I seem to have figured it out. Basically, you calculate the overall energy (heat) released by the condensation of the steam. This is more than enough to melt all 47g of ice. So now you have 47g of water at 0C, a fraction of the water from steam at 100C, and the remaining steam itself. Using...
Nothing seems to be working. I've tried every combination of signs (pos/neg) I can think of. Clearly I'm missing something from one of the equations. Even if I solve for the correct temperature, that is only half the solution.
Any other suggestions?
I realized I messed up the signs of Q(cold) in the equation when trying your first suggestion of making the second term of Q(hot) negative. So my answer of 342 was off. However even after fixing that issue, I get 115.8.
So...perhaps I'm misunderstanding, but as far as I can tell, I have...
with that in mind, solving for T yields 342.44, and unless I messed up something with units, that is already in Celsius. I would think the value would be between 0 and 100...
[SOLVED] Latent heat, steam and ice question
Homework Statement
14g of steam at 100C is added to 47g of ice at 0.0 degrees C.
a) Find the amount of ice melted and the final temperature.
Homework Equations
Q=mL
Q=mc\DeltaT
Q(hot)=-Q(cold)
The Attempt at a Solution
Ordinarily, in...