Recent content by thetrice

Thanks ghwellsjr, a far well written reply , yes you adequately describe my concern. Now this actually describes my question perfectly,My question is would the Earth observer see ship number 2(black) to be faster or slower ? or that only depends on from where i send the pulse ? as sometimes...

so according to the fourth observer what happens when 1st sends to the 2nd and third and when third sends to 1st and 2nd ?

The example given is as follows : we have 3 space ships(numbered from left to right) placed in space moving at velocity V in the same direction (they are moving to the right) , each one can send a pulse of light to the others and the others can determine time reached. so each of them is an...

In a case of a charged particle attracted to another fixed chrged particle both on one axis. force on charged particle will be F= (const)(q1*q2)/(r^2) for simplification = q1*q2*const =1 , and also mass of particle will be equal to one . so acceleration = 1/(r^2) r is distance between 2...

I have studied the physics content in serway , and ofcourse that's only the most basics of physics, but there are many directions and many theories that i have to study, so i would like you to tell me in what direction i should go to continue studying physics, rather than just opening Wikipedia...

yeah another way of explaining it(AFTER READING ABOVE POST): if u say that according to observer1 the mirror is not moving away from him and so is the light he sees the light moving upward in c and downward again and that what really happens as he can't see that light returned to flash light...

no i don't agree .. here what is wrong and i said about 200 times but seems everybody ignore it YOU said: yes it will come straight down but not back to his flashlight this observer emitted a flashlight straight upward moving with velocity C observer 1 is in the train. observer 2 is outside...

here is what i meant:(SOORY FOR BAD HAND WRITING):http://img693.imageshack.us/img693/9056/imgkqn.jpg

no in both cases they dont... as u have quoted it will return to its old position(which it started propagation) which is equal to the new position of the flash light- v*t @fredrik: ok here are the 3 events: 1- light emitted moving up. 2- light reflected from mirror 3- light is moving diagnolly...

PLEASE READ THE POSTS: no the speed in y direction won't be smaller as when calculated we substitute vY with c and vx with zero because if we made a train move with a v nearly to c then oobserver1(in the train) will surely realize that light didn't reflect and return back to the same position...

yes the light will return to the same position according to observer 2 as both are not moving(x-axis axis of motion where y-axis is along gravity) while observer1 (in the train)is the one moving so he will not see light returning to the same position. @janus: what experiment?? (any link or...

jeesm , the train will move horizontally or even diagonally according to observer2 but not the light , as the light have nothing to do with moving train and mirror as it will just start from postion1 and back to it(as i said million times above) and will not return to a new position(which was...

it seems you don't read my posts as i explained why should light start at pos (x,y) and return back to pos(x,y) while when the car and the observer 1 will be in pos(x+(t*V) ,y) and observer2 didnt even move so basically observer 2 and the light didn't move from their position and observer 1...

thats because the light will not be reflected back to the flash light but it will be reflected back to a postion = postion of the flashlight- (V*delta time)

please read the post above :) , as i said that the light cannot move diagonally in the first place as when it will reflect back it will reflect in the same position it started, so it will appear to observer1 as moving vertically not diagonally