Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Displacment equation of a charged particle

  1. Oct 29, 2011 #1
    In a case of a charged particle attracted to another fixed chrged particle both on one axis.
    force on charged particle will be F= (const)(q1*q2)/(r^2)
    for simplification = q1*q2*const =1 , and also mass of particle will be equal to one .
    so acceleration = 1/(r^2)
    r is distance between 2 particles, Another simplification is to assume r = X which is displacemnt of chrged particle(assuming fixed particle at fixed cordinates of(0,0,0) .
    so equation is accelration=1/(x^2)
    where x= velocity*time , velocity = initial velocity + acceleration *time.
    so how can i get displacment in variable of time ?
    Problem is that X is affected by v , v is affected by a , and a is affected by X. so its a loop.
  2. jcsd
  3. Oct 29, 2011 #2

    Simon Bridge

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    Putting both charges on the x axis...
    You need to solve:

    [tex]\frac{d^2x}{dt^2} = \frac{1}{x^2}[/tex]
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Displacment equation of a charged particle
  1. Charged Particles (Replies: 2)