1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Displacment equation of a charged particle

  1. Oct 29, 2011 #1
    In a case of a charged particle attracted to another fixed chrged particle both on one axis.
    force on charged particle will be F= (const)(q1*q2)/(r^2)
    for simplification = q1*q2*const =1 , and also mass of particle will be equal to one .
    so acceleration = 1/(r^2)
    r is distance between 2 particles, Another simplification is to assume r = X which is displacemnt of chrged particle(assuming fixed particle at fixed cordinates of(0,0,0) .
    so equation is accelration=1/(x^2)
    where x= velocity*time , velocity = initial velocity + acceleration *time.
    so how can i get displacment in variable of time ?
    Problem is that X is affected by v , v is affected by a , and a is affected by X. so its a loop.
     
  2. jcsd
  3. Oct 29, 2011 #2

    Simon Bridge

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    Putting both charges on the x axis...
    You need to solve:

    [tex]\frac{d^2x}{dt^2} = \frac{1}{x^2}[/tex]
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Displacment equation of a charged particle
  1. Charged Particles (Replies: 2)

Loading...