Recent content by TheYoungFella

I got the sense it was a well prepared answer from a person on a mission to prove Gods existence. He was quite clever he knew how to tangle me up in a more philosophical bent ie i can't 100% prove X so why is it a LAW etc etc. basically trying to get me to say we using faith in engineering and...

I found this post on the very subject in Yahoo Answers

I recently quoted the various laws of thermodynamics to someone recently and they replied that we could never prove that unless the universe was ordered. Obviously this would increase it's disorder and negate the measurement so how do we or can we prove entropy at all.

F=ma F=ma=(-mg-kv) a=\frac{dv}{dt} \frac{mdv}{dt}=(-mg-kv) \frac{mdv}{mg+kv}=-dt \int\frac{mdv}{mg+kv}=\int-dt \frac{m}{k}\ln{mg+kv}=-t+c mg+kv=\exp^\frac{-kt}{m}+c v=C\exp^\frac{-kt}{m}-\frac{mg}{k} v=v0 t=0...

F=ma F=ma=(-mg-kv) a=\frac{dv}{dt} \frac{mdv}{dt}=(-mg-kv) \frac{mdv}{mg+kv}=-dt \int\frac{mdv}{mg+kv}=\int-dt \frac{m}{k}\ln{mg+kv}=-t+c mg+kv=\exp^\frac{-k t}{m}+c v=C\exp^\frac{-k t}{m}-\frac{mg}{k} v=v0 t=0 v0=C\exp^\frac{-k}t{m}-\frac{mg}{k}...

Thanks for the tip man

[tex]\frac{mdv}{mg+kv}=-dt[\tex] [tex]\int\frac{mdv}{mg+kv}=\int-dt[\tex] [tex]\frac{m}{k}\ln{mg+kv}=-t+c[\tex] [tex]mg+kv=\exp^\frac{-k}{m}t+c[\tex] ah I can't for the life od me figure this fancy way of displaying the functions like you would on paper so I will gracefully withdraw.

Sorry I just took that part from my notes I just have first mdv/(mg+kv)=-dt then adding the intergration symbol integrate mdv/(mg+kv)= integrate -dt So I am quessing it's with respect to time as its to be as a function of time I really have only a vague idea what's going on here. I believe...

1. An object of mass, M, is projected into the air with an initial vertical component of velocity, Vo. If the air resistance is proportional to the instantaneous velocity, with the constant of proportionality being, K, derive the equations for the displacement, velocity and acceleration as...