Recent content by thindelgado

Ok, I think I'm getting it now. This would be my last counterargument I guess. So if the block was released from rest 1 m above the spring then with conservation of energy: mg(h+x) = .5kx^2 49.05 + 49.05x = 125x^2 x = .8526 m I'm assuming this is correct since pretty much the same scenario...

All right, here's my confusion though. If the block is originally at rest then it has no kinetic energy only gravitational potential. Once it starts descending (compressing) it has some kinetic but when it reaches the lowest it can get, for that moment all of its energy is in the form of spring...

Homework Statement Lets say I have a spring with a stiffness of k = 250 N/m originally unstretched. I then gently place a 5 kg block on top of the spring. How much does the spring compress? Homework Equations W = mg F = -ks mgΔh = 0.5k(Δh)2 The Attempt at a Solution Using...