Recent content by Thrawn

Homework Statement I need to know how to cancel terms in the equation Ve = sqrt 2(6.6742 x 10^-11 N m^2 / kg^2 (12.1kg))/0.106780959m Homework Equations Ve = sqrt 2(mu)/r Where r is the distance from the denter of the object to be escaped from, and mu is the Gravitational Constant...

So would the next step be: Ve = sqrt 2(6.6742 x 10^-11 kg m/s^2 m^2/kg^2 (12.1kg)/0.106780959m ? If not, then what?

6. A satilite is place in orbit 6.00x10^6. Jupiter has a mass of 1.90x10^7 and radius of 7.5x10^7. Find the orbital speed. ...6 x 10^6 Whats? Meters? Lemons?

The formula to calculate escape velocity is: Ve = sqrt 2(mu)/r Where r is the distance from the denter of the object to be escaped from, and mu is the Gravitational Constant multiplied by the mass of the object to be escaped from. All sai and done, this gives an equation of: Ve = sqrt...

Homework Statement Why, in the second step of the question, is 0.001 added to the right side? Part 2. In the equation Ve = sqrt 2(6.6742 x 10^-11 N m^2 / kg^2 (12.1kg))/0.106780959m I'm trying to calculate the escape velocity of an object, and have figured out everything up to this...

The end velocity should be equivalent to the escape velocity of the attractive mass, so I found that. On another note, does anyone know of a website (or book) which gives an introduction to calculus, starting at the very basics then working up?

And what would the Laplace Transform be? Does it help if I know the end velocity of the object?

What does the bottom part of the left side mean (dt)? EDIT: And for anyone who DOES know, How WOULD one go about solving this?

My calculations gave 1 226 seconds, so whatever we're doing wrong appears to be similar...

What is LRAM, and is it freeware?

Perhaps to restate my original question would be best: How do you calculate the amount of time it takes an object to travel towards another object, accounting for the inverse square law relation between distance and gravitational attraction?

But the end goal is to FIND the amount of time it takes... It doesn't make sense to give a value to time when time is what you want to find...

You can always use the computer notation, Eg 2 squared = 2^2. For that weird integral s thingy... well you can use italics, eg. f...close enough. EDIT: Or you could look for the correct equations, then copy them... The tags are easy enough: [ tex] [ \tex] (no spaces in actual tags)...

Using this, I get... t1 = t0 + dt ...? f = g*m1*m2/r0^2 0.0000000132944 N a = f/m1 1.32944 × 10^-7 m∕s^2 dv = dt*a ...? v1 = v0 + dv ...? dr = dt*v1 ...? r1 = r0 + dr ...? What would be the next...

What do the "delta"'s mean? What would the equation look like expressed in the format used in the example: F= Gmm/r^2 ? I'm a bit confused... are your equations individual or to be done separately, and how do they relate? Quick answer: Yes, at least I think...