Recent content by Threadlike

blkqi: Yup! That's clear enough now, thank you! kev: I think that last post of yours clears everything I had doubts about! Thank you!

EDIT: Checking the link! We didn't really take the acceleration transformation equation but I will try and digest it fully and come back to this thread. But, just by the looks of it, I think I pretty much understand intuitively what you're saying!

Thank you blkqi...That cleared it up a bit! If I understood this correctly: -Relativistic acceleration = du/dt and NOT (gamma^3)*(du/dt) -Therefore du/dt = (F/m)(1/(gamma)^3) From which we can easily get the answer that agrees with the theory. Please correct me if I'm wrong but that's about it...

Well this is where I'm puzzled! Isn't the relativistic acceleration supposed to be gamma^3*(du/dt)? So why exclude gamma^3? Sorry if I'm being rather annoying :(

Hello everyone! I apologize if my first post is of a problem that may seem like a really silly one. But it was something we were stuck with today in Modern Physics class. It is NOT a homework assignment! We have proved that relativistic force, F = m*(du/dt)*(gamma)3 where gamma is the Lorentz...