Well said
really i am not aware, also i think the larger amount of problems in the later editions transcended from the first in the 1960's. I am not familiar with the problems of Courant's book nor the publication date but i think Spivak's preceeds R. Courant book, again i am not sure.
Yes he is using Spivak's Calculus book.
Maybe a bit strange, but please consider that spivak himself said some of the problems are so difficult ( marked by the asteriks ) that even the brightest students will have to be really interested to continue trying to solve them. One problem in the...
cool .. i tried something different (dont know if it makes any sense)
n^6021=2007^2007
n^6021 can be written as 6021^n for any n
so we have n^6021=2007^2007
so we have log_6021 n = log_2007 2007
which is quite easy to solve for n
but what does this mean . if it means anthing at...
thanks, i saw that but it said nothing to me ( please excuse my ignorance ) so i hesistated to mention. so can some one explain how todo it the intelligent way! :rolleyes:
i don't .please help me out here ..i see if 2007 turn was reversed( or partially) then it becomes 7020 which maybe related in some way to 6021..maybe gcd.. help or mods ..i can't figure this way.
remember the rational function will produce a quotient, which when multiplied by the divisor will yeild the original R(z). So the second expression is in the form R(z) = quotient x divisor.
More specifically (z-a_j)^uj X S_j(z) .. Where as they said S_j(z) is the rational fuction ( which was...
taken from How to Solve It - A New Aspect of mathematical Method by G. Poyla.
Just wanted to share a piece of an interseting read from the classic.
I found of that passage this paragraph quite insightful:
So more generally what attitude should one have when it comes to studying (regardless of love or competition) and what is considered good study habits?