Recent content by thrive

which would mean that the answer to the question is false

it would mean there is some linear combination of c1, c2, c3 (not all zero) that would solve that first equation. In the second equation it would imply that not necessarily would there be a c4 to cancel the V4 term?

it would mean that the answer is false...

Homework Statement If V1...V4 are linearly independent vectors in R4, then {V1, V2, V3} are also linearly independent. True or False. The Attempt at a Solution My solution involved reducing the problem down the 3 vectors in R3. Then show a counter example of this in R3 although I...

no help?

Hello all, I am stuck on some homework, basically I am stuck on the problems dealing with proofs. I am not asking for complete answers just any direction would be helpful. 1) I have to prove the Grötzsch graph is not 3-colorable (vertex can be colored in such a way that no edge shares 2...

i don't understand how that works. how can he just change stuff inside the radical

edit: i got 3 as the answer

can i just do something like this sqrt(9x^2 + 4) -> 3x+2

is that is the correct problem...i have no clue how to simplify it algebraically...

I'm going to post the question and the work i have done thus far. I just need to know if I am on the right track with the problems and how I can go about simplifying them to finish them off. These are from a class homework assignment that will be graded. lim (sqrt((9x^2)+4))/x+3...

ok, so when showing my work I just go from: step 1: lim X-> 00 [xsin(1/x)] step 2: lim X-> 0 [sin(1/x)/(1/x)] step 3: = 1 so once we change the form from multiplying by x to dividing by 1/x we also change the limit going to infinity to go to 0?

so as x approaches infinity, v=1 as x approaches 0? I still don't understand this reasoning...

I understand this, however how can v just change from going to infinity to go to 0?

we already learned that lim x->0 [sin(x)/x] = 1 i just do not understand how the lim x->0 of [xsin(1/x)] relates to this