Linear Independence: V1-V4 in R4 - True or False?

thrive
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Homework Statement



If V1...V4 are linearly independent vectors in R4, then {V1, V2, V3} are also linearly independent. True or False.



The Attempt at a Solution


My solution involved reducing the problem down the 3 vectors in R3. Then show a counter example of this in R3 although I have not been able to come up with one.
 
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Why not assume that \{V_1,V_2,V_3\} are linearly dependent, what would that mean?
 
it would mean that the answer is false...
 
Obviously, but that doesn't prove anything.

Start by assuming \{V_1,V_2,V_3\} are linearly dependent, under that assumption, what could you say about the equation c_1V_1+c_2V_2+c_3V_3=0?

What would that imply about the equation c_1V_1+c_2V_2+c_3V_3+c_4V_4=0?
 
it would mean there is some linear combination of c1, c2, c3 (not all zero) that would solve that first equation. In the second equation it would imply that not necessarily would there be a c4 to cancel the V4 term?
 
thrive said:
it would mean there is some linear combination of c1, c2, c3 (not all zero) that would solve that first equation.

Right. So choose those values of c1, c2, and c3 and plug them into the second equation.

In the second equation it would imply that not necessarily would there be a c4 to cancel the V4 term?

If c_1V_1+c_2V_2+c_3V_3=0 then, c_4=0 would surely satisfy the equation c_1V_1+c_2V_2+c_3V_3+c_4V_4=0 right?

But if \{V_1,V_2,V_3\} are linearly dependent, then there would exist c_1, c_2 and c_3 not all equal to zero, so even if c_4=0 there would exist c_1, c_2, c_3 and c_4 not all equal to zero that would make c_1V_1+c_2V_2+c_3V_3+c_4V_4=0, which would mean what?
 
which would mean that the answer to the question is false
 
No, if there exist c_1, c_2, c_3 and c_4 not all equal to zero that would make c_1V_1+c_2V_2+c_3V_3+c_4V_4=0, would the set \{V_1,V_2,V_3,V_4\} be linearly independent or dependent?
 
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