Recent content by Timberhead

Resolved: I kept working with substituting ex = u on both μ's and it actually works insanely well.

I did initially, but found it problematic since it ends up becoming ½∫sinu/u. If you keep on doing it it winds up being a giant beast of an equation which doesn't appear to match μ2 at all. I thought part of it might equal μ2, but that didn't happen either. The two just keep mismatching cosine...

Homework Statement Solve by variation of parameters: y" + 3y' + 2y = sinex Homework Equations Finding the complimentary yields: yc = c1e-x + c2e-2x The Attempt at a Solution I set up the Wronskians and got: μ1 = ∫e-2xsin(ex)dx μ2 = -∫e-xsin(ex)dx The problem is that I have no idea how to...