Recent content by timmy1234

<N_a>=\frac{-1}{E_a-\mu}\frac{\partial}{\partial \beta}\log(Z_a)

First off, thanks for the replies! but i think my question didn't get across too well. the point i tried to make is the follwoing: if the pauli exclusion principle doesn't apply then one can use the Boltzmann distribution to determine how many partiles will be sitting on energy state Ei...

general version of fermi-dirac distribution?? merry x-mas everyone! in the Boltzmann distribution every state with energy Ei can be occupied by an arbitrarily large number of molecules. In contrast, if each state can be occupied by only one particle then one needs to use the fermi dirac...

hello kanato, wow thanks a lot for this crisp explanation! Can't believe Atkins hasn't a paragraph like this :) thanks again!

problem @altered-gravity if one computes the integral from E to infinity using the Boltzmann equation on gets what you wrote: \frac{n(E>E*)}{n_0}=exp(\frac{-E*}{RT}) however, if one takes (which i think in this case one has to) the maxwell-boltzmann distribution given by: C *...

anyone?

no thermodynamics experts here? :)

Hi folks! i'm a biologist trying to understand some basics of statistical mechanics. :wink: unfortunately, i cannot get over the following problem(s). A) in the Boltzmann distribution the fraction of particles with energy Ei is given by: \frac{Ni}{N} = \frac{exp(-\beta Ei)}{\sum...