Recent content by titasB

Hi! I'm considering a maters degree in mathematics as the title suggests. Right now I have to decide a specific topic and I've narrowed it down a bit but I'd like some input from people in the field (or getting into the field). I am inclined to research something applied in physics. Here's what...

Awesome thanks so much!

nn/ n! ≥ n

So something like this: an = ( n . n. n ... n ) / 1 . 2 . 3 ... n ) an =n [ ( n . n. n ... n ) / 1 . 2 . 3 ... n ) ] we can see the expression in the brackets approach infinity since the numerator is much larger than the denominator so, ∞ ≥ an ≥ n and since n → ∞ this gives : ∞ ≥ an...

Homework Statement Determine whether the sequence is convergent or divergent Homework Equations an = {nn / n! } The Attempt at a Solution an = ( n . n. n ... n ) / 1 . 2 . 3 ... n ) ⇒ an =n [ ( n . n. n ... n ) / 1 . 2 . 3 ... n ) ] ⇒ as n → ∞ , an → ∞ This is further confirmed by...

Thanks. Wasn't sure about the cos2(n) part

Homework Statement Determine whether the series is converging or diverging Homework Equations ∞ ∑ 1 / (3n +cos2(n)) n=1The Attempt at a Solution I used The Comparison Test, I'm just not sure I'm right. Here's what I've got: The dominant term in the denominator is is 3n and cos2(n)...

Hello!

But the the mistake is a few steps before that where the text reads "Multiplying out the last term on the right". The writer removes the brackets but only changes the sign for the first term of the brackets. It is supposed to be a minus sign in the denominator (as in a difference of the two terms).

I think you are right. The step only "divides both sides of the equation by the quantity in the large brackets on the left side" as the text states. So, the sign doesn't change and will be the sum of the two terms in the denominator as you wrote out above.

Check your differentiation for w with respect to t for the second order. Everything else seems to be fine

Take it step by step. First take the left hand side of what you want to prove, that is, the second derivative of w with respect to t. Next, do the same with the other side, that is find the second derivative of w with respect to x. (This step like the step before this will need you do some...

Sure :)

thank you

First, a / R = sin (c) => a = R sin (c) --- (i) Next, R^2 = a^2 + L^2 => a = (R^2-L^2)^1/2 ---(ii) Equating (i) and (ii) gives: R sin (c) = (R^2-L^2)^1/2 => R = L / cos(c)