Recent content by tmint

Homework Statement Here is the circuit: http://gyazo.com/1e11d9208da0aa29d10b72128844ad40 What is the Electric Potential at Point A? Battery 1: 6.76 V Battery 2: 11.8 V Resistance 1: 100Ω Resistance 2: 217Ω Resistance 3: 312Ω Homework Equations Kirchhoff's Rules V=IR The...

Oh okay, So 1.54(Current 3-Current 1)+3.6(Current 3-Current 1)=1.4 5.14(Current 3-Current 1)=1.4 5.14(Current 2)=1.4 Current 2= .27A! And I take this value and plug it in back, I get Current 1= -.593 A change the direction and I get Current 3= -.323 A change the direction...

Oh my mistake. So 3.6[Current 3-Current 1]=1.4 Oh you're right, this does work somewhat nicely. So 3.6[Current 3- Current 1]=1.4 Current 3- Current 1= .389 So Current 2= .389 , I'm kind of suspicious of this value. Its differs from what I got previously. Did I mess up again in my arithmetic...

Okay, 1.54[Current 3- Current 1]= 1.4 So [Current 3- Current 1]= 1.1 A So would Current 2 by that equal 1.1 A? Right? Would I then sub this back in for Current 3- Current 1 and solve for Current 1 in the first equation or is that wrong? Like so, -1.54[Current 1]+ 1.8[1.1 A]...

Thank you. Sorry for the notation I'll write it out to make it easier to follow. When I use Kirchhoff's rules I get the following equations: Let c be left of a, d left of b, f right of b, and e right of a Oh, and Current 1 is current from Battery 1, Current 2 from Battery 2 in the middle...

Diagram: http://gyazo.com/0b719e6d399ad894d2c48ce06d994672Homework Statement In the figure the resistances are R1 = 0.77 Ω and R2 = 1.8 Ω, and the ideal batteries have emfs ε1 = 2.1 V, and ε2 = ε3 = 3.5 V. What are the (a) current (in A) in battery 1, (b) the current (in A) in battery 2 and (c)...