Ahh yes...
using Mu*(N/L)*I, I returned a value of .0013 which fit nicely into my change in magnetic flux equation to give me the correct answer.
Thanks a lot!
Great.
The formula to find the field inside of a solenoid is B = Mu*Number of turns*Length of solenoid*I. Using this, I found the field to be 0.0113T.
Magnetic flux = BAcosPhi
When plugging in my B value from the field inside the solenoid and the area (Pi*r^2) of the coil and cos 0, my value is...
Homework Statement
A single coil with a radius of .02m is placed inside a 3m long solenoid that has 600 turns. The radius of the solenoid is 0.15m. The plane of the coil is perpendicular to the axis of the solenoid. The solenoid is connected to a battery, an ammeter and a switch. The ammeter...
Homework Statement
A beam of protons with v=1.8x10^8 are deflected 90 degrees by a constant magnetic field. The trajectory of the beam has a circular arc with a radius of 4m.
I am asked to find the magnitude of the constant magnetic field.
Homework Equations
I know that r=mv/eB. When...