Recent content by tornado28

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    Power Series for Volume of Balls in Riemannian Manifold

    Thanks. That gets me the first term, and at least gives me an educated guess for the second term. I'm guessing that \frac{d}{dr} \left( d(\exp_p)_{rv} \right) = ric_p(v). When you integrate this over the whole ball you end up getting the scalar curvature which is what was supposed to happen.
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    Power Series for Volume of Balls in Riemannian Manifold

    I'm trying to work out the following problem: Find the first two terms of the power series expansion for the volume of a ball of radius r centered at p in a Riemannian Manifold, M with dimension n. We are given that Vol(B_r(p)) = \int_S \int_0^r \det(d(exp_p)_{tv})t^{n-1}\mathrm{d}t...
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    What is the definition of compact sets in real analysis?

    You are being tripped up by the difference between a subset and a proper subset. If S is a set then U is a subset of S if each element of U is also in S. Thus every set is a subset of itself, and the empty set is a subset of every set. A proper subset is a subset that is not equal to the...
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    Qual Problem: When do Matrices Commute?

    Thanks. I found another thread with information about when matrices commute. Apparently two matrices commute iff they're simultaneously diagonalizable.
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    Qual Problem: When do Matrices Commute?

    Thanks morphism! (A-I)(B-I) = AB-A-B+I = AB-AB+I=I. Therefore B-I is the inverse of A-I so we have that I=(B-I)(A-I) = BA-A-B+I = BA-AB+I. Thus BA-AB = 0 as needed. How did you know to write it that way? Also, do you know any good general conditions related to matrices which commute...
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    Qual Problem: When do Matrices Commute?

    I'm preparing for a qualifying exam and this problem came up on a previous qual: Let A and B be nxn matrices. Show that if A + B = AB then AB=BA.
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    Tool To Allow User to Draw Knots

    For a school project, I would like to make a website that allows the user to draw http://en.wikipedia.org/wiki/Knot_(mathematics)" . In other words, I want to allow the user to draw many sided polygons (enough sides to approximate a curve) that are allowed to self intersect. There are two...
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    L^p Spaces and Convergence of Functions

    Ok, I understand why \|f_n-f\|_p \rightarrow 0 \Rightarrow \|f_n\|_p \rightarrow \|f\|_p , but I still don't have a solution for the other direction. In your solution, Vig, it is not necessarily true that 2^p( |f_n|^p+|f|^p-|f_n - f|^p) \geq 0 since we could, for instance, have f_n=1, f = -1...
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    Real Analysis / Advanced Calc Puzzler

    Ha, I get it now. Thats why it works. As I pointed out earlier we can assume that f is positive on (a, b). Since f(a) = f(b) = 0 and ln(0) = -\infty we have that ln(f(x)) \rightarrow -\infty as x \rightarrow a (or b). Now apply the mean value theorem twice, once on the interval (a+ \epsilon...
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    Real Analysis / Advanced Calc Puzzler

    Citan, that's a clever observation but how do you use it to solve the problem?
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    Real Analysis / Advanced Calc Puzzler

    Ok, made some progress. We will assume that f(x)>0 for x\in (a,b). (We could prove using a bit of topology that provided f is not identically 0 then there is a subinterval where this is true for either f or -f.) We want to use Darboux's theorem which requires that f'_+(a) exists, so first...
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    L^p Spaces and Convergence of Functions

    Thanks so much for your help! Here's another practice qual problem if you're interested. https://www.physicsforums.com/showthread.php?p=3436359#post3436359
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    Real Analysis / Advanced Calc Puzzler

    Let f:[a,b] \rightarrow R be a continuous function such that f(a)=f(b)=0 and f' exists on (a,b). Prove that for every real \lambda there is a c \in (a,b) such that f'(c) = \lambda f(c).
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    L^p Spaces and Convergence of Functions

    This is a functional analysis qualifying exam problem that I can't figure out. Any assistance would be appreciated since I have to take a similar qual soon. I was able to make some limited progress in the p=2 case using Holders inequality. Suppose f_n, f\in L^p where 1\le p <\infty and that...
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