Recent content by trinkleb

Oh wow, that makes a lot of sense. Thank you so much!

Alright, so when I use that equation I get: ΔΘ = ½(ωo + ωf)(t) ΔΘ = ½(0 + 0.2 rad/s)(6 s) = 0.6 rad = 34.4° The book says it should be 50.2°, which doesn't make sense to me. Is there a certain concept that I might be missing which could be keeping me from getting the right answer?

This is what I did using a kinematics equation: Θ = Θo + ωozt + 1/2(αzt2 Since it starts from rest, Θ = 1/2(0.0333 rad/s2)(6 s)2 Θ = 0.594 rad = 107° This is not the right answer. Does Θ really represent the angle between the acceleration and the velocity? I thought it was just the angular...

Here is the problem I am working on. I have found answers for all of them except part (f), which is the one I need help with. I will report the answers I have so far: A classic 1957 Chevrolet Corvette of mass 1240 kg starts from rest and speeds up with a constant tangential acceleration of 2.00...