Recent content by TristanRE

It completely slipped my mind! Thank you. I redid did it the same way except replacing P1 with PInitial=(8/3m,,p1,0,0) Thereby obtaining M = (m2-16/3mE)1/2, and Emax = 3m/16.

I'm not sure this is what you meant, but I ended up doing the following. P1 = incoming mass 4 momentum = (E1),p1,0,0) P2 = created particle = (E2,p1,-E,0) P3 = photon = (E,0,E,0) I then equate: P2=P1 - P3 I squared it and rearranged, and plugged in for E1 = 5/3m, which yielded M =...

Homework Statement A mass m moving at speed 4c/5 collides with another mass m at rest. The collision produces a photon with energy E traveling perpendicular to the original direction, and a mass M traveling in another direction. In terms of E and m, what is M? What is the largest value of E (in...

My apologies! I get so used to shortening it (no deltas) that I often forget they were ever there. It was a typo. I ran it again though, and I obtained 4L/3c for t'. Not sure how I did that. =/ I thought about it again though, and I believe I got the values for x' and t' incorrect for the...

I gave it a go with the LTs, thought I'm not sure I'm going through with it correctly. Here's what I did: Between claps Ground frame: x = L, t = 0 x' = Y(x-vt) = 5L/3 t' = Y(t-vt/c^2) = -5L/3c But now, for between the West clap and meeting the tree (what I need to know): x' = 0, t' = -5L/3c I...

Homework Statement "Two people stand a distance L apart along an east–west road. They both clap their hands at precisely noon in the ground frame. You are driving eastward down this road at speed 4c/5. You notice that you are next to the western person (W) at the same instant (as measured in...