Recent content by trollphysics

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    Finding theta in a ramp problem, given velocity, distance, accelration,and mu k,

    Yes the mistake was in the moving of the left hand side... Here is the proper way: a2-g2x2+(µ(gx)2+2(a(µ(gx)))= 0 Now can I substitute in the variables or do I have to do something else?
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    Finding theta in a ramp problem, given velocity, distance, accelration,and mu k,

    Would it come out to be: a2+g2-g2x2+(µ(gx))2 + 2(a(µ(gx))) = ? Is this correct? or am I just doing it wrong?
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    Finding theta in a ramp problem, given velocity, distance, accelration,and mu k,

    Hi tiny-tim, my teacher had told me that this was a quadratic equation. But I don't really know how to set that up. All I have now are these variables. Any help would be appreciated and thanks for letting me know of the signs which the forum integrates.
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    Finding theta in a ramp problem, given velocity, distance, accelration,and mu k,

    Homework Statement Velocity final is 8 m/s velocity initial is 0m/s acceleration is -1.6m/s2 distance is 20m Mk is .2Homework Equations My teacher has given me sin(theta)=(square root) of 1-cos^2(theta) and cos(theta) = xThe Attempt at a Solution I'm a bit stuck, the part which I am up to is...
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    How to find acceleration without mass?

    no i mean like on a slope. My teacher said that you don't need mass if you have M = mu. So on a 45 degree angle ramp. The delta x would be 30m. Then you would need you can cancel out the m's in a equation. no time. Just are given angle, delta x, mu
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    How to find acceleration without mass?

    Can someone explain to me how it is done? I know you cancel the m's out in a formula but how?
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