Recent content by tshah321

I don't understand, though. Doesn't each cutout have its own center of mass, therefore making it okay to use I = mr2?

The mass without the cutouts of the entire disk is 6kg, and with the cutouts it is 4kg. So the mass of all 4 cutouts is 2kg, so each cutout is 2kg/4 = 0.5kg. Is there something wrong there? Yes, so I believe I did that right, unless I missed something when finding the mass of each cutout. I...

Definitely missed that. So r = 0.03m, and then the mass of each is 0.5kg. The moment of inertia of each is I = mr2, so I = (0.5)(0.03)2 = 0.00045 kgm2 So I would just multiply that by 4, then subtract it from 0.0432? @SteamKing

Homework Statement What is the moment of inertia of the 4 kg disk below when it rotates about the center of mass? The mass of the disk without the holes is 6 kg . Homework Equations Center of mass equation: (1/M)(∫xdm) Moment of inertia of a disk: I = 0.5mr2 Parallel axis theorem: I = Io +...