yes you are right . I made a mistake ther i am editing it :
(C \sub{tot})^{-1} = (C1)^{-1}+(C2)^{-1}+...+(Cn)^{-1}
Callum 10, you have to do a little work with the information. S = Area = l * h
where l is the width of the plates given , equal for all plates. h = a + x
Remember that...
Since all the capacitors can be considered to be in series the equation to find the C
C \sub{tot} = (C1)^{-1}+(C2)^{-1}+...+(Cn)^{-1}
Next use C=(ε0*S)/d
where d is the distance between two plates.
Given that height of plate is a linear function of x, like h = a + x
as at x=0, h=a and...
The "problem" that leads to complex numbers concerns solutions of equations. All quadratic equations and Polynomials will have defined roots if we introduce complex numbers. for example
a) x^2 = 1 , has two roots: x= 1 and x = -1, both are real and you can visualise them on xy plot in a...
Johnf2004,
In the given quetion you are given the frequency,f i.e. number of revolutions per minute. You can convert this into time period, T using:
T = 2*pi/f
Now use v = \frac{2 \pi r}{T}
as for an object moving with constant speed on a circular path, v = s/t
Here, the distance,s is...
How about this approach : The current I = I1 + I2
where I1 is current through 4k and I2 is current through 8 K resistor. Since I1 = I2/2 Therefore I = 9.75 mA
Now assume the current flowing in anticlockwise direction through the loop The parallel combination gives 8/3 K resistor. For this...
Data is right use the product rule to find first derivative and in finding the second derivative also.
\frac{d(x\tan x)}{dx}=\tan x +x\sec^{2}x
\frac{d^2(x\tan x)}{dx^2}= \frac{(2)(\cos{x} +x\sin{x})}{\cos^3{x}}
The answer in book is right. The length of side1, |\vec{X}| is obtained by
\vec{X} = \frac {\vec{a} - \vec{b}}{2}
The length of side 2 is, |\vec{Y}|
\vec{Y} = \frac {\vec{a} + \vec{b}}{2}
The angle, \theta between two sides can be found by X.Y and the other angle would be =...
Now since it is given that a and b are unit vectors , therefore |a| = 1 and |b|=1
so (6a + b).(a-2b) = 4 - (11/2) = -3/2
Now are you able to get the result ?
in I-V graphs voltage represents the potential difference . Usually current starts for a positive potential difference. For linear devices R = V.I
There is no difference in current behaviour on reversing the polarities i.e. even for negative voltages, so the forward bias behaviour is same as...
4(a+b-c) = 3(a+b-c)
This statement can be true only if (a+b-c) = 0
If you try to divide both sides by ( a+b-c) then it becomes 0/0 i.e. indeterminate form of the function. hence 4 is never equal to 3, at least not for a mathematician.