Recent content by twostep08

im still not sure what exactly my drawing should look like? i know that the 2 angles should be 45 degrees apart which they are. so ill rotate the drawing counter clockwise 9 degrees? and then have my new stress values coming out of it? or the old stress values? I am still not getting it, so...

so for the principal angle, i just rotate the square 9 degrees counter clockwise? do i do anything for the shear angle? and on this new figure, would the forces now be perpendicular to the shape or to the original axis?

thanks ill go check into my signs. and a_s is the associated angle of the shear (alpha sub s). there is a diagram of a square showing the perpendicular and parallel forces acting on it, but how can i redraw the new configuration?

id like to think i did this right, but i just want to make sure. i can't do symbols so let d equal sigma. the stress components are d_xx= 200 MPa, d_xy= 50 MPa, d_yy=-100 MPa. I need to find the max shear stress, and the principal stresses, and then a_s and a_p. heres what i got: max...

1. HIPS is a : a)Polystyrene-Polybutadiene blend b)High Impact Polybutadiene Blend c)Polystyrene-Polybutadiene copolymer blended with polystyrene and polybutadiene d)High polystyrene matrix material I'm pretty sure it's not B, and I'm leaning towards C, but I'm not very confident...

Homework Statement A bar of material is 1ft long and has a cross sectional area of 2 square inches. If a force of 10,000 lbs is put on the bar, what is the stress? Homework Equations stress= force (in pounds)/ area (square inches) The Attempt at a Solution this seems very easy...