Does Length Affect Stress Calculation in Material Science?

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SUMMARY

The discussion centers on calculating stress in a material science context, specifically using a bar that is 1 foot long with a cross-sectional area of 2 square inches under a force of 10,000 lbs. The formula for stress is defined as stress = force (in pounds) / area (in square inches), leading to a calculated stress of 5,000 psi (pounds per square inch). The length of the bar is deemed unnecessary for this specific stress calculation but may be relevant for future strain calculations.

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Homework Statement



A bar of material is 1ft long and has a cross sectional area of 2 square inches. If a
force of 10,000 lbs is put on the bar, what is the stress?

Homework Equations



stress= force (in pounds)/ area (square inches)

The Attempt at a Solution


this seems very easy, but the "1 foot long" in the equation is throwing me off. I've never done these kind of questions before, so i don't know how to handle it. My gut is telling me to just do 10,000 / 2 = 5000 and the "1 foot long" is unnecessary info in there to throw you off, but then again, there could easily be some other calculation i need to do...Also, what unit would the 5000 be in (assuming that's the right answer). Thanks a lot (i want to make sure i know what I'm doing, so please only answer if you are 100% sure you're right)
 
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I'm guessing the 1 foot long refers to another part of the question where you will have to calculate the strain. (and the change in length of the bar)
The unit you get if you divide pounds by square inches is pounds per square inch. That is a unit of pressure, though I haven't used those units since about 1967!
 

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