If we look at the formula before completing the square, j(x) = 2x^2 - 8x + 5 = c, if I input the values that I previously worked out they somehow appear to be correct.
If we input these values into the square, such that c > -3, for example, -2.
j(x) = 2x^2 - 8x + 5 = -2
2x^2 - 8x + 7=0
If we...
So relooking at the link I find the part where the part that is now the only part with x's is equal to what becomes, with simplification, the root, and because the root has to be positive/negative, we can say that:
2(x-2)^2 - 3 = c
2(x-2)^2 = c + 3
The second part being what we are looking...
Understanding how to complete the square, I come to 2(x-2)^2 - 3. I've used this for functions so this part all makes sense, in order to get the simplified form of the function, yet I am still confused as to how this is useful in finding c.
if 2(x-2)^2 - 3 = c
2(x-2)^2 - 3 - c = 0 or something...
Homework Statement
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For which values of c, cER, will the equation j(x) = c have real roots?
Homework Equations
j(x) = 2x^2 - 8x + 5
The Attempt at a Solution
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I understand I need to get this into the form of b^2 - 4ac, yet I do not understand why this is important and such. From my...