Recent content by ual8658

Oh so just the centroid of an area basically? But only take the x-component of the centroid if its a vertical force.

I get how to find vertical and horizontal forces on a submerged surface (vertical = weight of fluid and horizontal = force on vertical projection). I also get how to find the point of application for the horizontal force using a moment balance. But how do you determine the point of application...

Thank you. This makes sense.

This is for a design class, not practice but it still has to be realistic. You're saying that at high speeds, the air cushion of a traditional air bearing will almost disappear because of friction?

When I said high speeds, I was talking about speeds between 100-200mph. Right now we're working with a smooth, metal track surface that has plus or minus 1 mm height differences at the gaps. Would these air bearings survive impacts at those speeds with such height variations?

Our design is supposed to support between 1/2 - 1 ton of weight moving at high speeds. Would an air puck design suffice for such parameters?

Are there any good research papers or established theories on using skis with either porous air bearings or an air skirt with holes to send pressurized air out? One of my concerns right now is the stability of a ski (ie any particular shape each ski/section should be and whether we should divide...

Alright thank you so much! This was according to my professor the hardest problem we'd see for this topic so thanks a lot for your guidance.

Thank you so much for the graph. I understand what happens when we shift the graph using cosine instead and I get that answer as well (.411 s). In regards to if I used the original equations, I first obtain -0.089 seconds. Am I correct to assume that the regular cosine and sine curves...

I'm not following. Also if I do translate the curve to cosine as you suggested, I still don't get the right answer.

The n = 1,2,3 is supposed to signify that that the function oscillates and will repeat the behavior again. I guess he did just change the variable Also if I shift like you suggested, I get -0.1 2 pi sin (2 pi t) + cos ( 2 pi t) = 0 which gives me tan (2 pi t ) = 1/ (0.1 2 pi) which doesn't get...

If I were to shift the curve, would I be shifting both the d/dt (sine) and sine curves or just one curve? So the input would become sin((2 pi t) + pi/2)? Also my professor gave me this when I asked him: Somehow he got that from the relationship I wrote down (the one with sine and cosine). Is...

That's what I did: tan( 2pi t) = -.1 2pi from the equation I got up there( 0.1 (2 pi) cos(2 pi t) + sin( 2 pi t) = 0. But if I were to solve for it I get a negative time.

Yes something like this but not precise: SOS. What's that darn identity. I tried setting tan( 2pi t) = -.1 2pi but I get a negative time?

Homework Statement Homework Equations The Attempt at a Solution My problem lies in when I get equations like: and if I plug in Vi and its derivative, I get equations like: How do I solve for t in these equations if I have a sine and a cosine term that contain t?