Recent content by ubermuchlove

yes, but i am still clueless as to how to incorporate alpha. im honestly missing something big here?

let h1= top of the snowball and h2= the height at which she loses contact K1 + U1 = K2 + U2 0 + mgh1 = mgh2 + 1/2mv^2 gh1 = gh2 + 1/2v^2 g(h1-h2)= 1/2v^2 v^2/R (h1-h2) = 1/2v^2 h1-h2=R/2 h2= h1-R/2 this is as far as i got. h2 is the point at which the skier looses contact.

wait so, in that case Ko+ Uo = Kf + Uf 0 + (12)(9.8)(2) = (1/2)(4)(v^2) + (4)(9.8)(2) i get a v that is twice the answer. the answer is 4.4

Homework Statement A skier starts at the top of a very large, frictionless snowball, with a very small initial speed, and skis straight down the side. At what point does she lose contact with the snowball and fly off tangent? That is, at the instant she loses contact with the snowball, what...

Conservation of Energy Homework Statement A system of two paint buckets connected by a lightweight rope is released from rest with the 12.0 kg bucket 2.00 m above the floor. Using the principle of conservation of energy to find the the speed with which this bucket hits the floor. You can...

this is what i have... after taking the derivative of U(x), i got F(x)= -C[SIZE="1"]6/6x^[SIZE="1"]7. And this force is an attractive force. Im not sure about the last part.

Homework Statement The potential energy of a pair of hydrogen atoms separated by a large distance x is given by U(x)= -C[SIZE="1"]6/x^[SIZE="1"]6, where C[SIZE="1"]6 is a positive constant. What is the force that one atom exerts on the other? Is this force attractive or repulsive?Homework...