Recent content by UchihaClan13

  1. UchihaClan13

    Derivation of Applied Force in a Grade 12 Force Question

    Set dF/dθ=0 get θ and substitute back to get F
  2. UchihaClan13

    I Why is b>1 and x,y positive in logarithm definition?

    A simple doubt came to my mind while browsing through logarithmic functions and natural logarithms we define $$\log_b(xy) = \log_b(x) + \log_b(y)$$ Here why is the condition imposed that b>1 and b is not equal to zero and that x and y are positive numbers? Is it something to do with the...
  3. UchihaClan13

    Circular + Projectile Motion question

    Okay dokie I'll just check your expression but dimensionally,it's correct Now,use the equation of trajectory to determine your final coordinates And also remember energy conservation P.S.A hint: choose your coordinate axeses carefully:smile::smile::smile::wink: UchihaClan13
  4. UchihaClan13

    Circular + Projectile Motion question

    DO you mean the center to be the origin(the starting point of the ball would then have the coordinates 0,-R)UchihaClan13
  5. UchihaClan13

    Circular + Projectile Motion question

    What do you mean when you say "the center of coordinate" Does this refer to a specific set of coordinates or is this trivial?UchihaClan13
  6. UchihaClan13

    Circular + Projectile Motion question

    The first logical step would be to presume that the ball covers a major portion of the circular track so as to simplify the projectile motion calculations And how did you get v=gRsinx? Your L.H.S has units of metre/second while your R.H.S has units of Metre^2/Second^2 UchihaClan13
  7. UchihaClan13

    Classical Where Can I Find Volume 1 of 'Advanced Problems in School Physics'?

    Hi there,everyone I am in need of the following book "Advanced Problems in School Physics" Volume 1( By Cengage Learning) I have volume 2 But no matter how hard I try, I can't get the first volume( it's either out of stock or is currently unavailable etc.) I would greatly/deeply appreciate it if...
  8. UchihaClan13

    Is a=g/3 the only solution or are there other possible solutions?

    I see what you mean Since the first derivative of g is zero,it implies g is a constant And we already have da/dt=0 from the problem statement So this would force dk/dt=0 meaning k would be a constant Thanks a lot for your help UchihaClan13
  9. UchihaClan13

    Geometrical optics, refraction

    Glad you could realize it UchihaClan13
  10. UchihaClan13

    Geometrical optics, refraction

    Is the object placed in the first medium?? (The rarer one?) I can give you small hints But I cannot give you the entire answer
  11. UchihaClan13

    Is a=g/3 the only solution or are there other possible solutions?

    Yeah sorry That's what I did But y=kx (say) Doesn't this lead to y=f (x) For different values of x, won't we have different values of y The only difference with this case and my original one is that In my original one, both were constants While in this one, both are variables X being the...
  12. UchihaClan13

    Are You on AoPS and Have You Tried the Physics Marathon?

    How many of you guys are on AoPS? And if you are, have you guys attempted the physics marathon?UchihaClan13:smile::smile:
  13. UchihaClan13

    Is a=g/3 the only solution or are there other possible solutions?

    I can post the rest of the solution if required All I need is some confirmation UchihaClan13
  14. UchihaClan13

    Is a=g/3 the only solution or are there other possible solutions?

    Homework Statement xg=x*(dv/dt)+v^2 is a differential equation Which has a solution of the form v=at Where a is a constant.Find a Homework Equations dv/dt=v*(dv/dx) V=dx/dt A=dv/dt=d^2x/dt^2The Attempt at a Solution I assumed 'a' as a function of g That is a=kg for some constant k And...
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