Recent content by UchihaClan13

Set dF/dθ=0 get θ and substitute back to get F

A simple doubt came to my mind while browsing through logarithmic functions and natural logarithms we define $$\log_b(xy) = \log_b(x) + \log_b(y)$$ Here why is the condition imposed that b>1 and b is not equal to zero and that x and y are positive numbers? Is it something to do with the...

Okay dokie I'll just check your expression but dimensionally,it's correct Now,use the equation of trajectory to determine your final coordinates And also remember energy conservation P.S.A hint: choose your coordinate axeses carefully:smile::smile::smile::wink: UchihaClan13

DO you mean the center to be the origin(the starting point of the ball would then have the coordinates 0,-R)UchihaClan13

What do you mean when you say "the center of coordinate" Does this refer to a specific set of coordinates or is this trivial?UchihaClan13

The first logical step would be to presume that the ball covers a major portion of the circular track so as to simplify the projectile motion calculations And how did you get v=gRsinx? Your L.H.S has units of metre/second while your R.H.S has units of Metre^2/Second^2 UchihaClan13

Thanks a ton!:)

Hi there,everyone I am in need of the following book "Advanced Problems in School Physics" Volume 1( By Cengage Learning) I have volume 2 But no matter how hard I try, I can't get the first volume( it's either out of stock or is currently unavailable etc.) I would greatly/deeply appreciate it if...

I see what you mean Since the first derivative of g is zero,it implies g is a constant And we already have da/dt=0 from the problem statement So this would force dk/dt=0 meaning k would be a constant Thanks a lot for your help UchihaClan13

Glad you could realize it UchihaClan13

Is the object placed in the first medium?? (The rarer one?) I can give you small hints But I cannot give you the entire answer

Yeah sorry That's what I did But y=kx (say) Doesn't this lead to y=f (x) For different values of x, won't we have different values of y The only difference with this case and my original one is that In my original one, both were constants While in this one, both are variables X being the...

I can post the rest of the solution if required All I need is some confirmation UchihaClan13

Homework Statement xg=x*(dv/dt)+v^2 is a differential equation Which has a solution of the form v=at Where a is a constant.Find a Homework Equations dv/dt=v*(dv/dx) V=dx/dt A=dv/dt=d^2x/dt^2The Attempt at a Solution I assumed 'a' as a function of g That is a=kg for some constant k And...

The equation which you used Is correct Just set the boundary conditions And use proper sign convention (If the light ray is incident from the denser medium to the rarer, the image distance and radius are positive and the object distance is negative) Remember that the image formed is a real one...