A simple doubt came to my mind while browsing through logarithmic functions and natural logarithms
we define
$$\log_b(xy) = \log_b(x) + \log_b(y)$$
Here
why is the condition imposed that b>1 and b is not equal to zero and that x and y are positive numbers?
Is it something to do with the...
Okay dokie
I'll just check your expression but dimensionally,it's correct
Now,use the equation of trajectory to determine your final coordinates
And also remember energy conservation
P.S.A hint: choose your coordinate axeses carefully:smile::smile::smile::wink:
UchihaClan13
The first logical step would be to presume that the ball covers a major portion of the circular track so as to simplify the projectile motion calculations
And how did you get v=gRsinx?
Your L.H.S has units of metre/second while your R.H.S has units of Metre^2/Second^2
UchihaClan13
Hi there,everyone
I am in need of the following book
"Advanced Problems in School Physics" Volume 1( By Cengage Learning)
I have volume 2
But no matter how hard I try, I can't get the first volume( it's either out of stock or is currently unavailable etc.)
I would greatly/deeply appreciate it if...
I see what you mean
Since the first derivative of g is zero,it implies g is a constant
And we already have da/dt=0 from the problem statement
So this would force dk/dt=0 meaning k would be a constant
Thanks a lot for your help
UchihaClan13
Yeah sorry
That's what I did
But y=kx (say)
Doesn't this lead to y=f (x)
For different values of x, won't we have different values of y
The only difference with this case and my original one is that
In my original one, both were constants
While in this one, both are variables
X being the...
Homework Statement
xg=x*(dv/dt)+v^2 is a differential equation
Which has a solution of the form v=at
Where a is a constant.Find a
Homework Equations
dv/dt=v*(dv/dx)
V=dx/dt
A=dv/dt=d^2x/dt^2The Attempt at a Solution
I assumed 'a' as a function of g
That is a=kg for some constant k
And...