What Object Distance Ensures a Real Image in Geometrical Optics?

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SUMMARY

The discussion centers on determining the object distance required for a real image formation in geometrical optics, specifically involving a spherical surface with a radius of curvature of 10 cm separating two media with refractive indices of 3/2 and 4/3. The correct object distance must be less than 90 cm to ensure a real image is formed. Participants emphasized the importance of applying the correct sign convention and boundary conditions when using the formula for refraction at a spherical interface. The realization that the object must be placed in the rarer medium was a key point in reaching the solution.

PREREQUISITES
  • Understanding of spherical surfaces in optics
  • Knowledge of refractive indices and their implications
  • Familiarity with the sign convention in optics
  • Proficiency in using the refraction formula for spherical interfaces
NEXT STEPS
  • Study the derivation and application of the refraction formula at spherical interfaces
  • Learn about sign conventions in geometrical optics
  • Explore the implications of refractive indices on image formation
  • Investigate real and virtual image formation in different optical setups
USEFUL FOR

Students of optics, physics educators, and anyone involved in optical design or analysis seeking to understand image formation through spherical surfaces.

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Homework Statement


A spherical surface of roc 10 cm separates 2 media x and y of refractive indices 3/2 and 4/3 respectively. Centre of the spherical surface lies in the denser medium. An object is placed i x medium. For image to be real, the object distance must be ----

A) >90 cm

B) <90 cm

C) >80 cm

D) <80 cm

Homework Equations

- i don't know relevant questions[/B]

The Attempt at a Solution


I used the formula u2/v - u1/u = (u2 - u1)/R. Where u2= 3/2 and u1= 4/3. But i don't think that that is right.
 
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The equation which you used
Is correct
Just set the boundary conditions
And use proper sign convention
(If the light ray is incident from the denser medium to the rarer, the image distance and radius are positive and the object distance is negative)
Remember that the image formed is a real one and thus will converge at one point or the other in the denser or the rarer medium
The distance of the image will be measured from the boundary obviously
The formula
Is used is
That for
Refraction at A Spherical Interface

UchihaClan13
 
Object dist. Tending to infinite? And img dist. 'f'? That didn't gave me the answer. Please post the exact solution.
 
Is the object placed in the first medium??
(The rarer one?)
I can give you small hints
But I cannot give you the entire answer
 
UchihaClan13 said:
Is the object placed in the first medium??
(The rarer one?)
I can give you small hints
But I cannot give you the entire answer
I got it. I placed object in the wrong medium. My bad
 
UchihaClan13 said:
Is the object placed in the first medium??
(The rarer one?)
I can give you small hints
But I cannot give you the entire answer
I got it. I placed object in the wrong medium. My bad
 
Glad you could realize it
UchihaClan13
 

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