What Object Distance Ensures a Real Image in Geometrical Optics?

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Homework Help Overview

The discussion revolves around determining the object distance required to ensure a real image in the context of geometrical optics, specifically involving a spherical surface separating two media with different refractive indices.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the application of the refraction formula at a spherical interface and question the placement of the object in relation to the media. There are discussions about boundary conditions and sign conventions, as well as the implications of the object being in the correct medium.

Discussion Status

Some participants have offered guidance on the correct application of the formula and the importance of sign conventions. There is acknowledgment of a misunderstanding regarding the object's placement in the media, which has prompted further reflection on the problem setup.

Contextual Notes

There is a mention of imposed homework rules that prevent the sharing of complete solutions, leading to hints being provided instead. The original poster expresses uncertainty about the relevant equations and conditions for the problem.

ak127a
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Homework Statement


A spherical surface of roc 10 cm separates 2 media x and y of refractive indices 3/2 and 4/3 respectively. Centre of the spherical surface lies in the denser medium. An object is placed i x medium. For image to be real, the object distance must be ----

A) >90 cm

B) <90 cm

C) >80 cm

D) <80 cm

Homework Equations

- i don't know relevant questions[/B]

The Attempt at a Solution


I used the formula u2/v - u1/u = (u2 - u1)/R. Where u2= 3/2 and u1= 4/3. But i don't think that that is right.
 
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The equation which you used
Is correct
Just set the boundary conditions
And use proper sign convention
(If the light ray is incident from the denser medium to the rarer, the image distance and radius are positive and the object distance is negative)
Remember that the image formed is a real one and thus will converge at one point or the other in the denser or the rarer medium
The distance of the image will be measured from the boundary obviously
The formula
Is used is
That for
Refraction at A Spherical Interface

UchihaClan13
 
Object dist. Tending to infinite? And img dist. 'f'? That didn't gave me the answer. Please post the exact solution.
 
Is the object placed in the first medium??
(The rarer one?)
I can give you small hints
But I cannot give you the entire answer
 
UchihaClan13 said:
Is the object placed in the first medium??
(The rarer one?)
I can give you small hints
But I cannot give you the entire answer
I got it. I placed object in the wrong medium. My bad
 
UchihaClan13 said:
Is the object placed in the first medium??
(The rarer one?)
I can give you small hints
But I cannot give you the entire answer
I got it. I placed object in the wrong medium. My bad
 
Glad you could realize it
UchihaClan13
 

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