Recent content by UCrazyBeautifulU

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    Rotational Kinematics & Energy

    Thanks for all the wonderful help!!
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    Rotational Kinematics & Energy

    what is wrong with the formula? Only one speed is given.
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    Rotational Kinematics & Energy

    A 10.7 g CD with a radius of 6.06 cm rotates with an angular speed of 30.9 rad/s. What is its kinetic energy? What angular speed must the CD have if its kinetic energy is to be doubled? Here is my work: kinetic energy energy = 1/2 m v2 = 1/2 m ( r ω )2...
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    Potential Energy & Conservative Forces #18

    what's the conservation of energy equation i should use? thanks.
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    Potential Energy & Conservative Forces #18

    what's the equation i should use?
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    Potential Energy & Conservative Forces #21

    yeah, my math was off. Thanks, i figured it out.
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    Potential Energy & Conservative Forces #18

    f_cp = ma_cp = mv^2 / r okay, I still have the velocity missing in this equation, so what do I do?
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    Potential Energy & Conservative Forces #21

    1/2kd^2 - u_k(mgx) = 1/2mv_f^2 +mg(0) Solve for d I got d= 0.090595 incorrect answer can anyone else help me with this one?
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    Potential Energy & Conservative Forces #20

    i get 0.423 = 0.529308 + 1.7672 x 10^-4 Which gives a negative answer. Using what you wrote above I get k = 1166.9 and that answer was not correct.
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    Potential Energy & Conservative Forces #20

    .5k(0^2) = 0 so how do I get anything when I can't even solve for k?
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    Potential Energy & Conservative Forces #20

    yeah, i did, then you have to square it. I wrote my numbers up above that I was using in the equation. YOu end up with -0.105862 = 706.88(k)
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    Potential Energy & Conservative Forces #20

    i end up with a negative answer.
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    Potential Energy & Conservative Forces #18

    how do i figure out the velocity and the acceleration? I need the velocity for the centripetal force equation & I need the acceleration for the f=ma equation. thanks so much.
  14. U

    Potential Energy & Conservative Forces #20

    .5(0.348)(1.56^2) + .5(.348)(0^2) + .5k(0^2) = .5(.348)(1.56^2) + .5(.348)(v/2)^2 + .5k(1.88 x 10^-2)^2 those are all my numbers....is that right?
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