Recent content by Ummiya

Sorry I didn't see your first reply till now.

Mk is mu. (k for kinetic) ƒ is the frictional force T is the tension None of those are given.

Homework Statement A mass m1 on a horizontal shelf is attached by a thin string that passes over a frictionless pulley to a 2.4 kg mass (m2) that hangs over the side of the shelf 1.4 m above the ground. The system is released from rest at t = 0 and the 2.4 kg mass strikes the ground at t = 0.85...

Right. So what can I do at this point? The answer would still be wrong (55.58 seconds). I tried again by not rounding the numbers and keep them true to their value but still didn't get the answer in the practice.

I'm not sure, but I assume from this: "The time the speeder continues at constant velocity is sum of the times required for the three constant-acceleration segments of the police officer's chase."

Then should I be setting two equations equal to each other? There's this note, it's online practice so after you get the answer wrong you get this: "The time the speeder continues at constant velocity is sum of the times required for the three constant-acceleration segments of the police...

I assumed that when you said that the speed of the car was constant throughout the whole chase and that the police woman had to catch up to that speed. Also, the answer for how long it took for the police woman to catch up to the car says 62.7 seconds in my practice. I don't know which...

t(total) = 1.58 + 7.3 + 46.7 = 55.58 seconds 33 m/s?

Okay so then using the same equation again with zero acceleration now because she is maintaining the speed. 1900 = 360 + 33t 1540 = 33t t = 46.7 s It took the officer 46.7 seconds to reach the 1900 meter position from the 360 meters position.

So using v(t) = v0 + at 33 = 0 + 4.5t t = 7.3 s It took the officer 7.3 seconds to reach the speed of 119 k/h (33 m/s). And x(t) = x0 + v0t + 0.5at^2 x(t) = 0 + 33(7.3) + 0.5(4.5)(7.3)^2 x(t) ≈ 360 The officer has traveled 360 meters during this time.

(Sorry I wrote it as a police car chasing a motorcyclist. It's a motorcycle officer chasing a car.) Right, so that would make the velocity and everything else zero. I calculated the point after the officer chases the car which honestly, to me, the numbers don't make sense. I'm sorry I'm really...

This is a practice problem very similar to my homework question just with different values. 1. Homework Statement A motorcycle officer hidden at an intersection observes a car driven by an oblivious driver who ignores a stop sign and continues through the intersection at constant speed. The...