I've checked the Internet and this forum, and while I notice the term, "tuning resolution" used in different contexts, I can't find a definition. Can anyone provide a clear and concise definition or explanation?
Thanks both of you for your help.
I eventually solved it by using a half-angle formula on [cos(t)]^2, and then using a trig product formula on the resulting expression. I got the same answer as HallsofIvy.
Thanks again, guys!
Hey guys!
I'm stuck on a Laplace transform. Following is the problematic function:
[cos(t)]^3
Seems simple, but I'm having issues doing the Laplace transform on odd trigonometric functions. When I use the half-angle formula, I get this, which I can't seem to solve:
1/2cos(t) +...
I'm interested in how to understand exactly how radio waves will propagate in a particular situation. I know that they are absorbed by metal and water, pass through other materials albeit with loss of power, and reflect or bounce off of surfaces as well.
How do I know whether a radio wave will...
Dbouchard:
Great explanation; completely explained 1.f.i. for me. Thanks a lot!
Matter Wave:
Your first paragraph made sense; thanks for the new information about the change of the MR curve with the implementation of a price ceiling.
However, I got lost in your last paragraph...
This link (http://www.collegeboard.com/student/testing/ap/economics_micro/samp.html?micro has a list of released Microeconomics AP free-response questions. I have a question concerning the 2011 primary released exam.
See the questions here...
So, my answer for part (iii.) is 0.4 A/s, but I'm not sure whether there should be a minus sign in front, because I don't know whether the capacitor is charging or discharging. What should I do?
Thanks, gneill.
I see now. I always thought that the V in 1/2QV referred to the battery voltage, not the capacitor voltage. Thanks!
Would you mind explaining when the minus sign due to Lenz's Law is relevant? Do I use it when calculating the time rate of change of the current? -LdI/dt +...
I didn't mean voltage on the capacitor - I meant the voltage source in the circuit. If 1/2QV can be used to calculate energy stored in the capacitor at any point in time BEFORE the switch is flipped in a normal RC circuit, then can't I just transfer that value over if I know the switch was...
Thanks, gneill.
(i.) is easy. The energy stored in a partially charged capacitor is \stackrel{1}{2}QV
In our case, we get \stackrel{1}{2}(.105)(9.0) = 0.4725 Joules
(ii.) is harder. The total energy we have to work (or play) with is the amount of energy stored in the capacitor at time...
Homework Statement
Pages 6 and 7 http://apcentral.collegeboard.com/apc/members/exam/exam_information/2008.html
I am struggling with Question (2), Part (b), Sections (ii.) and (iii.)
Homework Equations
RL circuit with battery: I = V/R(1 - e-Rt/L), Imax=V/R
RC circuit with battery: I =...
Think about it.
a = f + 2g really means that a at 3 will equal f at 3 added to twice the value of g at 3. The latter information is given you in your table; just do the addition.
But how to calculate the derivative of a? That's where the point of the whole problem comes into play. The...
2x3 + 2y3 - 9xy = 0
To find the lines tangent to this curve, take the derivative:
6x2 + 6y2\frac{dy}{dx} - 9y - 9x\frac{dy}{dx} = 0
2x2 - 3y = 3x\frac{dy}{dx} - 2y2\frac{dy}{dx}
(2x2 - 3y) / (3x - 2y2) = \frac{dy}{dx}
It is now merely a matter of setting the denominator equal to...