Mindscrape,
I saw a different question and yea you are right but then let me ask you this; If you have a 10 kN vector that's on 270 degrees and it in compression, will the positive right because -(-9)=9?? is that correct
Thanks for the reply i appreciate the example you gave. But i thought when it comes to vectors it doesn't matter if they're in tension or compression unless its a truss because we only want the magnitude of each force. F2 and F4 were both in compression however F2 was negative but F4 was positive
The answers are
Rx = 34.87 Kn
Ry = 41.84 Kn
R = 54.5 Kn
angle = 50.2
Sorry for any inconvenience guys, but the answers given are correct because i asked my cousin and he said "hypythetically, if you have 3 Fy forces are going in one direction e.g. all facing down (which are negative)...
Yea i agree with you but they can't do the same error twice. This other questions has 4 forces:
F1 = 60 at 40 degrees (tension)
F2 = 50 at 110 degrees (compression)
F3 = 30 at 160 degrees (tension)
F4 = 40 at 270 degrees (compression)
when adding the Fy components they have F4 as...
The original probem asks to calculate the resultant of the three forces
F1 = 6kN at (0 or 360 degrees)
F2 = 8 Kn at 240 degrees
F3 = 10 Kn at 210 degrees
The solution they show is:-
Fx= 8cos240-6-10cos210
I understand everything except how they get -6. And by the way all the forces...
When adding the resultant of two or more forces i get confused when adding forces that are on 360 and 270 degrees. Like the question is 6 Newtons on 360 degrees, i don't get how they get -6, when cos 360 is 1
can anyone help me??
In this circuit, please tell me how they got the 4 ohms and the 12 ohms in parrallel when they look like they are in series
Please help me i am so desperate for an answer!