I agree that it is probably not the best, but we are not allowed to use compressed gases, so the only other option would be a propeller. I chose powered wheels over the propeller just for ease of operation and design (this is an entry-level freshman year project might I add, not a senior design...
I have an engineering project to do this semester. I'm not going to get into the specifics, but I (and my group) are going to be building a submersible servo-driven vehicle (it is basically driving underwater). The vehicle will be made of 4" PVC piping (thin-walled sewer variant). It must be...
Reading over it again, is this just referring to an AC step-down transformer? If so then I was already planning on using one anyway. I guess I didn't make it clear that I wasn't simply going to use the power straight from the 50A recepticle to spark an arc. I want to use a transformer to convert...
Is there any practical way to prevent this from happening? As you have mentioned commercial arc welders already do this.
Another thought I had was to use a car battery to power the arc furnace, keeping it completely off-grid. A typical car battery can theoretically supply 200A for around 15...
This. I won't necessarily always be trying to melt electrically conductive material.
This is actually something else I want to do too, but as I said above I won't always be trying to melt a material that this can work with. I suppose I could heat a conductive medium with induction and conduct...
What exactly is harmonic noise, and how do arc welders/furnaces cause it? Would the power company really care that much about it running for only a few minutes on rare occasions? I'm not talking about going into the metal ingot casting business or anything.
I apologize in advance for anything...
I'll be using it for several different purposes. If I work with an oxidation-sensitive material, then I will operate the furnace in an inert environment, such as argon gas. This will affect the behavior of the arc though, no? Since argon has about a fifth of the dielectric strength of air.
For...
I'm highly interested in building my own small arc furnace for hobby use. Thus, I want to understand the nature of electrical arcs before proceeding to have maximum control over my design. So far, I know that electrical arcs form when the dielectric strength of the material (in this case, a gas)...
Alright, I'm going to try my best to explain what exactly I'm looking for. Modeling the orbit of a planet with the solution I posted above will give me the orbit flat against the plane of reference with the perihelion lined up with the reference direction (the positive x-axis). I use the orbital...
I was looking at this image on Wikipedia, and its definition for the argument of periapsis is the angle on the orbital plane between the periapsis and where the orbital plane intersects the reference plane. Is this not what I want? If you rotate the orbital plane counter-clockwise (in a relative...
One last question, what do you call the angle between the semi-major axis and the x-axis of an arbitrary coordinate system? I already know that this is the orbital inclination when viewing the system from the side, but I'm talking about when viewing the system top-down. In other words, the angle...
Yeah, I would have done that had I wanted to. Unfortunately like I said I'm stubborn and I was trying my best to solve this non-iteratively. However after much frustration I have given up that notion. Unfortunately again, I'm still stubborn and want to solve it myself given Kepler's equations...
Perhaps. That's assuming that black holes and wormholes are similar animals, and they very well could be completely different since nobody has even discovered a wormhole yet, and we know next to nothing about black holes.
However my biggest complaint about the scientific accuracy of the movie...
Alright, I've done some work and I've found the integral I needed and thus a closed-form solution for A as a function of θ. I then plug this in for A in Kepler's law:
\frac{A}{t} = \frac{\pi ab}{P_o}
And attempt to solve for θ. The integral is really quite nasty, so I made some substitutions...
Ok, so in a last-ditch effort to find a closed-form solution to the problem (I'm stubborn like that) I tried to integrate the polar equation of the ellipse to get the area swept out at θ. I have gotten to a point where I must integrate this:
A = \int {\frac{1}{2} (\frac{b^2}{a - c\cos\theta})^2...